Solve this.
Dear Student,
In given statement, CH3COOH is 10% by weight. This means that CH3COOH is 10 g in 100 g of solution. This tells that water is 90 g. To calculate molarity,
Mass of solute = 10 g
molar mass of solute = molar mass of CH3COOH = 60 g/mol
volume of solution = mass of solution/density of solution = 100/1.2 = 83.33 ml
= 2
Molarity = 2 M
To calculate molality,
Weight of solvent = 90 g
= 1.85
Molality = 1.85 m
Answer is (2).
Regards
In given statement, CH3COOH is 10% by weight. This means that CH3COOH is 10 g in 100 g of solution. This tells that water is 90 g. To calculate molarity,
Mass of solute = 10 g
molar mass of solute = molar mass of CH3COOH = 60 g/mol
volume of solution = mass of solution/density of solution = 100/1.2 = 83.33 ml
= 2
Molarity = 2 M
To calculate molality,
Weight of solvent = 90 g
= 1.85
Molality = 1.85 m
Answer is (2).
Regards