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Dear student
The given expansion has the highest degree term of x2 which multiplied by power 11 will give highest degree of expansion=22


Let the expansion of (2x2-3x+1)11=a0+a1x+a2x2+...+a22x22Put x=1(2(1)2-3(1)+1)11=a0+a1+a2+...+a22a0+a1+a2+...+a22=0 __________________(1)Put x=-1(2(-1)2-3(-1)+1)11=a0-a1+a2-a3+a4-...+a22a0-a1+a2-a3+a4-...+a22=6 _____________(2)Adding equation 1 and 22(a0+a2+a4+...+a22)=6a0+a2+a4+...+a22=3

 

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