Solve this:

Solve this: In an A.C. sub-circuit as shown in figure, the resistance R = 0.2 Q. At a certain instant V 0.5 V A1 - 8 AIS / = 0.5 A, and current is increasing at the rate of — - T e inductance of the coil is (2) 0.02 H (4) 05 H (3) 0.01 H 0.05 H

Hi there!!!
Volt = emf - IR
emf =  volt + IR
emf = 0.6

emf = L dI/dt
    L= 0.6/80

Inductance = 0.05

Hope my answer helps u .......
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KAUNSI CLASS KA QUESTION H..
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V=e+iR 0.5=e+(0.2)(0.5) e=0.4 e=L(di/dt) L=0.4/8 L=0.05H
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Hopefully it ll help...

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