# Solve this:

$17a)2.47\times 100\phantom{\rule{0ex}{0ex}}=\frac{247}{\overline{)100}}\times \overline{)100}\phantom{\rule{0ex}{0ex}}=247\phantom{\rule{0ex}{0ex}}18)WeightofRenu=27.5kg\phantom{\rule{0ex}{0ex}}Weightofhermother=1.12\times 27.5kg\phantom{\rule{0ex}{0ex}}=\frac{112\times 275}{1000}\phantom{\rule{0ex}{0ex}}=\frac{112\times 11}{40}\phantom{\rule{0ex}{0ex}}=\frac{28\times 11}{10}\phantom{\rule{0ex}{0ex}}=\frac{308}{10}\phantom{\rule{0ex}{0ex}}=30.8kg\phantom{\rule{0ex}{0ex}}Thus,theweightofhermotheris30.8kg$

Regards

**
**