Solve this:

Solve this: 6 thrown ) Sum •a total O' at 9.

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Please find below the solution to the asked query:

11 ) We Probability P ( E )  = $\frac{\mathrm{Total} \mathrm{number} \mathrm{of} \mathrm{desired} \mathrm{events} \mathrm{n} ( \mathrm{E} )}{\mathrm{Total} \mathrm{number} \mathrm{of} \mathrm{events} \mathrm{n} ( \mathrm{S} )}$

Here  ,

n ( S ) = Total number of cards = 10     

i ) To find probability of getting a odd number , We find total number of ' odd number ' of cards , So

n ( E ) = Total number of ' odd number ' of cards = 5

So,

Probability of getting a odd number = $\frac{5}{10} = \frac{\mathbf{1}}{\mathbf{2}}$                                     ( Ans )

ii ) To find probability of getting a ' Y ' card, We find total number of  ' Y ' cards, So

n ( E ) = Total number of  ' Y ' cards = 3

So,

Probability of getting a ' Y ' card = $\frac{\mathbf{3}}{\mathbf{10}}$                                     ( Ans )

iii ) To find probability of getting a ' G ' card, We find total number of  ' G ' cards, So

n ( E ) = Total number of  ' G ' cards = 2

So,

Probability of getting a ' G ' card = $\frac{2}{10} = \frac{\mathbf{1}}{\mathbf{5}}$                                     ( Ans )

iv ) To find probability of getting a ' B ' card bearing number > 7 , We find total number of  ' ' B ' card bearing number > 7 , So

n ( E ) = Total number of  ' B ' card bearing number > 7 = 0

So,

Probability of getting a ' B ' card bearing number > 7 = $\frac{0}{10} =\mathbf{0}$                                     ( Ans )

Hope this information will clear your doubts about topic.

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