Solve this:

Dear student

Beaker I : Mg +  H2SO4  -->MgSO4 +  H2
Hydrogen gas is released, which burns with a pop sound.

Beaker II :  Graphite does not react with water under normal conditions

Beaker III : Al+CuSO4  ---> Al2(SO4)3 +Cu
A reddish brown deposit is seen over the Al rod

Beaker IV: Cu+ HCl --->CuCl2 + H2
Copper reacts with HCl, to form a blue solution of Copper chloride.

Hence observation in beaker II is wrong.
Thus correct option is B

Regards
 

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