Dear student, Q 5 Total weight of cauliflowers bought = 412kg=92kg Weight of each cauliflower = 14kg So number of cauliflower he bought = 92÷14=92×4 = 18 6 Distance travelled by sumit=623km=203km and time taken=113=43hours In 43hrs, the distance travelled is 203km So, in 1 hour, the distance travelled = 203÷43=203×34=5 km For remaining queries we request you to post them in separate threads to have rapid assistance from our experts Regards

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Solve this: Vijay If each weigh, each. how many cauliflower* he bur travel" km in hours. How in L bottles contain litres of water. What Shilpa has bought kg Of dry fruit,_ She want, to pack than in gift packs of kg each. HOW many gift packs Will be able to make? L of a liquid has to be poured equally into bottles. How much liquid will each bottle hold? A fast moving train is km away from a tunnel. If it covers L km in each second, how many seconds will it take to enter the tunnel? ACTIVITY YOU WILL NEED a sheet of graph paper and coloured pencils STEPS 1. Draw four 4 4 grids with 16 squares, each on the graph paper. Name them gid A, B, C and D, respectively. 2. Follow the instructions and make patterns by colouring the squares within the grids. Grid A: Colour — Of the squares blue and L in pink. Total number of small squares in grid A — 16. L of 16 -L x 16 8. So, 8 squares will be 2 coloured blue and the other 8 squares pink. 3. Now make patterns in other three grids. 12 Grid B: Colour — or squares red and — or —6 squares green. Grid C: Colour — squares blue, — squares red and — squares orange. 16 2 — purple and 16 16 pink, - - Grid D: Colour - 8 To access more worksheets on fractions, visit rsgr.in;pearlsS. Click on LINK under For more activities see page 185.

Dear student,
Q.5. Total weight of cauliflowers bought =

4 \frac{1}{2} k g = \frac{9}{2} k g

Weight of each cauliflower =

\frac{1}{4} k g

So number of cauliflower he bought =

\frac{9}{2} \div \frac{1}{4} = \frac{9}{2} \times 4 = 18

D i s \tan c e t r a v e l l e d b y s u m i t = 6 \frac{2}{3} k m = \frac{20}{3} k m a n d t i m e t a k e n = 1 \frac{1}{3} = \frac{4}{3} h o u r s

I n \frac{4}{3} h r s, t h e d i s \tan c e t r a v e l l e d i s \frac{20}{3} k m . S o, i n 1 h o u r, t h e d i s \tan c e t r a v e l l e d = \frac{20}{3} \div \frac{4}{3} = \frac{20}{3} \times \frac{3}{4} = 5 k m

For remaining queries we request you to post them in separate threads to have rapid assistance from our experts.

Regards

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