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Solution,
Magnetic field due to a finite current carrying wire is given by the formula:
B=μoi4πacosθ1+cosθ2

In the present case, θ1=45o , θ2=0o 
Thus, the magnetic field at the point P due to both the arms of the arrangement is
B=2×μoi4πacos45o+cos0oB=2×μoi4πa12+1B=μoi2+122πa
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