Solve this :

Dear Student,

$$\begin{gathered} 2) i) \frac{3}{5} and \frac{5}{7} \\ \frac{3}{5}\times \frac{7}{7} and \frac{5}{7}\times \frac{5}{5} \\ \frac{21}{35} < \frac{25}{35} \\ Therefore, \frac{3}{5} < \frac{5}{7} \\ ii) \frac{-7}{2} and \frac{5}{2} \\ \frac{-7}{2} < \frac{5}{2} as negative number is always smaller than positive number \\ iii) -3 and 2\frac{3}{4} \\ -3 < 2\frac{3}{4} as negative number is always smaller than positive number \\ iv) -1\frac{1}{2} and 0 \\ -1\frac{1}{2} < 0 as negative number is always smaller than 0 \\ v) 0 and \frac{3}{4} \\ 0 < \frac{3}{4} as 0 is always smaller than positive number \\ vi) 3 and - 1 \\ 3 > -1 as negative number is always smaller than positive number \end{gathered}$$

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