Dear Student, Please find below the solution to the asked query: We havefx defined for x∈-3,2Hence -x will go from -3,0When x∈ -3,0 graph goes from -2 to 2Hence range for y=f-x is -2,2 OptionAAs x∈-3,2Hence x∈0,3but graph is defind for x≤2 only⇒x∈0,2Hence x∈-2,2 OptionBDomain of fx+1 will be Hope this information will clear your doubts about this topic If you have any doubts just ask here on the ask and answer forum and our experts will try to help you out as soon as possible Regards

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Solve this: 6. The figure illustrate graph of the function y = f(x) defined in [—3,2]. Identify the correct statement(s) ? NJ,A5 Range of y = is [—2,21 Domain of y = f(lxl) is [—2,2] CYDomain of y = f(lxl + I) is [—1,11 YRange of y = f(lxl + I) is [—100] o O

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Please find below the solution to the asked query:

We have f (x) defined for x \in [- 3, 2] Hence - |x| will go from [- 3, 0] When x \in [- 3, 0] graph goes from - 2 to 2 Hence range for y = f (- |x|) is [- 2, 2] . . Option (A) As x \in [- 3, 2] Hence |x| \in [0, 3] but graph is defind for x \leq 2 only \Rightarrow |x| \in [0, 2] Hence x \in [- 2, 2] . . Option (B) Domain of f (|x| + 1) will be

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Solve this: Solve this: 6. The figure illustrate graph of the function y = f(x) defined in [—3,2]. Identify the correct statement(s) ? NJ,A5 Range of y = is [—2,21 Domain of y = f(lxl) is [—2,2] CYDomain of y = f(lxl + I) is [—1,11 YRange of y = f(lxl + I) is [—100] o O

Solve this:

Solve this: 6. The figure illustrate graph of the function y = f(x) defined in [—3,2]. Identify the correct statement(s) ? NJ,A5 Range of y = is [—2,21 Domain of y = f(lxl) is [—2,2] CYDomain of y = f(lxl + I) is [—1,11 YRange of y = f(lxl + I) is [—100] o O