Solve this:

Solve this: tynsiciiy salt is Y (replaceable is (total charge on cation) Solution : of on molecule is zero A' and positive integers. Therefore, then X-2 Y —3 then X 2 Y-2 and .V-2 Therefore basicity of salt is 2 and its acidity is 4. (v) Equivalent mass of basic salt : Molar nuss of basic salt Eq, mass of basic salt Replaceable OH gps in basic ...00) A basic salt is one which has replaceable OH gpseg, etc. EXAMPLE 21 Calculate equivalent mass of (a) NaH2P04, and (b) Na:HP04. Solution ENaH Na:HP04 (Two H are replaceable) (One H is replaceable) EXAMPLE 22 Calculate equivalent mass of H2S04. NaH2P04 and in the reaction :

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Your question seems to be unclear, so I am assuming that you want the detailed solution of Example 21. If you still have any doubts regarding this topic, then we request you to please repost your question with complete information regarding it. So, that our experts can help you in a better way.

Please find below the solution of example 21:

For calculating the equivalent mass of these compounds we use the following relation-

Equivalent mass = $\frac{\mathrm{Molar} \mathrm{mass} \mathrm{of} \mathrm{the} \mathrm{acidic} \mathrm{salt}}{\mathrm{Replaceable} {\mathrm{H}}^{+} \mathrm{ions} \mathrm{of} \mathrm{the} \mathrm{acidic} \mathrm{salt}}$    (as we know that, both the salts are acidic salts)

• NaH₂PO₄ -

          Molar mass = 120 g/mol
          Replaceable H⁺ ions = 2

          Therefore, Equivalent mass =  $\frac{120}{2}$
                                                       = 60 g eq^-1

• Na₂HPO₄ -

          Molar mass = 142 g/mol
          Replaceable H⁺ ions = 1

          Therefore, Equivalent mass =  $\frac{142}{1}$
                                                       = 142 g eq^-1

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