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Solve this: Ä•alar quant iO 400 m a morn•ng he the tmck and at the other end, the dastano• and the displacement o/ the : distance covered by the pernon equab length of the track. It is equal to r.R 40-0 m = 126m. The displacement is equal to the diameter of the æmi-circular track joining the two ends. It is 2 R = 2 x 40-0m = 80 m. The direction of this displacement is from the initial point to the final point. 3.3 AVERAGE SPEED AND INSTANTANEOUS SPEED The ave

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Distance covered by person = Total path travelled = \frac{Circumference}{2} = \frac{2 πr}{2} = πr = \frac{22}{7} \times 40 = 126 m Displacement = Shortest distance between initial and final position = Diameter of track = 2 \times r = 2 \times 40 = 80 m

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