Solve using elimination method :
-3x+3y=4 , -x+y=3 

Dear Student.

$$\begin{gathered} The given set of equations is incorrect \sin ce dividing the first equation by 3 we get: \\ -x+y=\frac{4}{3} \\ and the second equation given is: \\ -x+y=3 \\ The solutions of such equations do not exist \sin ce the same expression on the left is giving two values which is not possible. \end{gathered}$$
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