Solve using elimination or substitution method..

Dear Student,

 bx/a + ay/b = a² + b² ......... eq1

x + y = 2ab .... eq 2..

frm eq 1.. b²x + a²y / ab = a² + b²

-> b²x + a²y = a³b + b³a

-> b²x - b³a = a³b - a²y

->b² ( x - ab ) = a² ( ab - y )

-> frm eq 2 ... b² ( x - x/2 + y/2 ) = a² ( x/2 + y/2 - y )

-> b² ( x/2 - y/2 ) = a² ( x/2 - y/2 )

-> b²x - b²y = a²x - a²y

-> x ( b² - a² ) = y ( b² - a² )

-> x = y ..

put the value of x in eq 2.... 2y = 2ab

Regards!