Solve
Ok we know that when RR x rr , in the F1 it produces all pink and in the F2 red, pink and white in the ratio 1:2:1.
We just need to remember that in F1 - we cross the parents(similar or diff genotypes) and in the F2 we cross the F1 progeny with itself. Always.
So since in this case we are getting the F2 ratio in F1 itself.
So the two parent have to be Rr and Rr.
Here in this ques we can also eliminate. The ques mention 'the parents' indicating both the parents are of the same genotype. So we can cross out RR - since RR x RR - will give all red plant.
rr x rr - will give all white plants
and rrrr doesn't even fit the norm as it shows a dihybrid prototype but with a single character (colour) into consideration ---- leaving behind Rr.
Hope this helepd ! :))
We just need to remember that in F1 - we cross the parents(similar or diff genotypes) and in the F2 we cross the F1 progeny with itself. Always.
So since in this case we are getting the F2 ratio in F1 itself.
So the two parent have to be Rr and Rr.
Here in this ques we can also eliminate. The ques mention 'the parents' indicating both the parents are of the same genotype. So we can cross out RR - since RR x RR - will give all red plant.
rr x rr - will give all white plants
and rrrr doesn't even fit the norm as it shows a dihybrid prototype but with a single character (colour) into consideration ---- leaving behind Rr.
Hope this helepd ! :))