$$\begin{gathered} Solve and verify it \\ \frac{y+\frac{3}{4}}{2y-\frac{1}{3}}=\frac{-6}{5} \end{gathered}$$

Please find below the solution to the asked query:

We have : $\frac{y + {\displaystyle \frac{3}{4}}}{2 y - {\displaystyle \frac{1}{3}}} = \frac{- 6}{5}$ , So

$$\begin{gathered} \Rightarrow \frac{{\displaystyle \frac{4y + 3}{4}}}{{\displaystyle \frac{6 y - 1}{3}}} = \frac{- 6}{5} \\ \Rightarrow \frac{4y + 3}{4}\times \frac{{\displaystyle 3}}{{\displaystyle 6 y - 1}} = \frac{- 6}{5} \\ \Rightarrow \frac{12 y + 9}{24 y - 4} = \frac{- 6}{5} \\ \Rightarrow 60 y + 45 =- 144 y + 24 \\ \Rightarrow 204 y = -21 \\ \Rightarrow y = -\frac{21}{204} \\ \mathbf{\Rightarrow }\mathit{y}\mathbf{ }\mathbf{=}\mathbf{ }\mathbf{-}\frac{\mathbf{7}}{\mathbf{68}}\mathbf{ }\mathbf{ }\mathbf{ }\mathbf{ }\mathbf{ }\mathbf{ }\mathbf{ }\mathbf{ }\mathbf{ }\mathbf{ }\mathbf{ }\mathbf{ }\mathbf{(}\mathbf{ }\mathbf{Ans}\mathbf{ }\mathbf{)} \end{gathered}$$
Hope this information will clear your doubts about topic.