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sin inverse 4/5 - cos inverse 15/17 = tan inverse 2x/1-x square

sin-145-cos-11517=tan-12x1-x2As we know that cos-1x+sin-1x=π2So π2-cos-145-cos-11517=tan-12x1-x2π2-cos-145×1517-1-4521-15172=tan-12x1-x2we have used the formula, cos-1x+cos-1y=cos-1xy-1-x21-y2π2-cos-11217-2485=tan-12x1-x2sin-13685=tan-12x1-x2sin-13685=sin-12x1+x22x1+x2=368585x=18x2+1818x2-85x+18=0
After solving using Shreedharacharya we will get
x= 85±852-4×18×1836
or x = 4.5 and 0.222

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