sonu and monu had adjacent triangular fields with common boundary 25m. The other 2 sides of sonu's field were 52m and 63m, while of monu's field were 114m and 101m . If the cost of fertilization is Rs 20per sq m, then find the total cost of fertilization for sonu and monu togeother.

Area of sonu's field using Heron's formula,
                       s = (25+52+63)/2
                        s = 70
  Area = √s(s-a)(s-b)(s-c)
           = √70(70-25)(70-52)(70-63)
           = √70(45)(18)(7) 
           = √396900
           = 630
So, area of sonu's field is 630m².
Area of monu's field,
         s = (25+114+101)/2
         s = 120
Area = √120(120-25)(120-114)(120-101)
         = √120(95)(6)(19)
         = √1299600 = 1140
So, area of monu's field = 1140m².
Total area = area of monu's field + area of sonu's field
                 = 1140+630
                 = 1770m²
As it costs 20 rupees per m²
  So, 1770*20
       = 35400r
So, it'll cost 35400 rupees together.

Hope it'll help!!!!!!!!