State Kirchoff's laws of an electrical network.Using  Kirchoff's laws,calculate the potential difference across the 8 ohm resistor


Let I1 is the current through the cell of 4 voltI2 is the current through 6 voltSO current through 8 ohm is I1+I2Taking the loop of first loop,−4 +2I1+8(I1+I2) +6I1 = 0−6+4I2+8(I1+I2)+1I2 = 02I1+8(I1+I2) +6I1 = 44I2+8(I1+I2)+1I2 = 616I1+8I2 = 48I1+13I2 = 68I2−26I2=4−1218I2 = 8I2 = 8/18 = 4/9 AI1 = (6−13×49)/8 = 1/36 Acurrent across 8 ohm = 1/36 + 4/9 = 17/36 Avoltage = V = IR = 1736×8 = 34/9 volt
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State krichhoff's law of an electrical network using krichhoff's law calculate the potential difference across the 8 ohm

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Using kirchoffs law calculate the potential difference across the 8ohm resistor
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Dusing kirchoff law determine the potential difference across 8 ohm resistanvce
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34/9 V is the P.D 8 ohm resistor

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