state whether the funtion is even or odd fx=log(1-x/1+x) Share with your friends Share 0 Atul Shaw answered this Dear Student, f(x)=log1-x1+xPut x=-x f(-x)=log1-(-x)1+(-x) f(-x)=log1+x1-x f(-x)=log1-x1+x-1 f(-x)=-log1-x1+x [log am=m log a] f(-x)=-f(x)Thus signal is odd. Regards 0 View Full Answer Aryan Yaduvanshi answered this Hii everyone 0