state whether the funtion is even or odd fx=log(1-x/1+x)

Dear Student,
 f(x)=log1-x1+xPut x=-x f(-x)=log1-(-x)1+(-x) f(-x)=log1+x1-x f(-x)=log1-x1+x-1  f(-x)=-log1-x1+x   [log am=m log a] f(-x)=-f(x)Thus signal is odd.
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