Subtract the sum of 3x + 2y + z and 5x – 3y + 7z from the sum of 4x + 3y and 2y – 3z.
[(4x+3y)+(2y-3z)] - [(3x+2y+z)+(5x-3y+7z)]
=[4x+3y+2y-3z] - [3x+2y+z+5x-3y+7z]
=[4x+5y-3z] - [8x-y+8z]
=4x+5y-3z-8x+y-8z
=-4x+6y-11z
=[4x+3y+2y-3z] - [3x+2y+z+5x-3y+7z]
=[4x+5y-3z] - [8x-y+8z]
=4x+5y-3z-8x+y-8z
=-4x+6y-11z