Subtract the sum of 3x + 2y + z and 5x – 3y + 7z from the sum of 4x + 3y and 2y – 3z. 

  [(4x+3y)+(2y-3z)] - [(3x+2y+z)+(5x-3y+7z)]
=[4x+3y+2y-3z] - [3x+2y+z+5x-3y+7z]
=[4x+5y-3z] - [8x-y+8z]
=4x+5y-3z-8x+y-8z
=-4x+6y-11z

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Hi Cherish dear
First write those following the word "from"
4x + 3y + 2y - 3z 
==> 4x + 5y - 3z
Change the sign of those to be subtracted. Here first we have to find the sum of two given
3x + 2y + z + 5x - 3y + 7 z 
==> 8x - y + 8z
​Now change the sign as - 8x +y -8z
​Now add to the one already written
So 
4x + 5y - 3z - 8x + y - 8z 
===> - 4x + 6y - 11z
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-4x+6y+4z
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-4x+6y-11z
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why
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What are you looking for?