sum of 1st 15 term is 240.Find the 8th term

X8=a+7d=16
  • 0
S15=240
Sn=n/2[2a+(n-1)d]
n=15 
S15=15/2[2a+14d]
240=15/2[2a+14d]
480=15[2a+14d]
32=2a+14d
​a+7d=16
8th term, a8=a+7d
                    =16
so, 8th term=16







14d]
32=2a
 
  • 1
Please find this answer

  • 0
What are you looking for?