sum of first p , q and r terms of an A.P. are a , b and c respectively. Prove that :

a/p (q-r) + b/p(r-p) + c/r (p-q) = 0

please make the correction, by the symmetry 2nd is b/q(r-p)

sum of first p , q and r terms of an A.P. are a , b and c respectively. Prove that :

a/p (q-r) + b/p(r-p) + c/r (p-q) = 0

let the first term of AP be A and common difference be d.

sum of the first p terms is

sum of the first q terms is

sum of the first r terms is

now

which is the required result.

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