sum of the areas of two squares is 640 m2.if the difference of their perimeters is64m,find the sides of the two squares.

Let the length of the side of the smaller square be x metre.

Perimeter of the smaller square = 4x metre.

Now, perimeter of the bigger square is 64 metre more than the perimeter of the smaller square.

Therefore, perimeter of the bigger square = (4x + 64) metre

Length of the side of the bigger square = = (x + 16) metre

Now, sum of the area of the two squares is 640 m^{2 }.

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