Suman made an arrangement with shaded and unshaded paper sheets as shown .Find the total area of the shaded paper sheets used in making the arrangement. FAST PLEASE .

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$$\begin{gathered} \mathrm{Take} \mathrm{one} \mathrm{part} \\ \mathrm{So} \mathrm{in} \mathrm{total} \mathrm{large} \mathrm{triangle} \mathrm{and} \mathrm{shaded} \mathrm{triangle} \\ \Rightarrow \frac{4}{2}=\frac{4}{2} \mathrm{so} \mathrm{these} \mathrm{large} \mathrm{and} \mathrm{small} \mathrm{triangle} \mathrm{is} \mathrm{similar} \mathrm{triangles} \\ \mathrm{Now} \mathrm{let} \mathrm{unknown} \mathrm{side} \mathrm{of} \mathrm{shaded} \mathrm{triangle} \mathrm{is} \mathrm{x} \\ \Rightarrow \frac{4}{2}=\frac{3}{\mathrm{x}} \\ \Rightarrow \mathrm{x}=1.5 \mathrm{cm} \\ \mathrm{So} \mathrm{now} \mathrm{area} \mathrm{of} \mathrm{shaded} \mathrm{triangle} \left(2,2,1.5\right) \\ \mathrm{s}=\frac{2+2+1.5}{2}=2.75 \\ \Rightarrow \mathrm{Area} \mathrm{of} \mathrm{one} \mathrm{shaded} \mathrm{triangle}=\sqrt{\mathrm{s}\left(\mathrm{s}-\mathrm{a}\right)\left(\mathrm{s}-\mathrm{b}\right)\left(\mathrm{s}-\mathrm{c}\right)} \\ \Rightarrow \mathrm{A}=\sqrt{2.75\left(2.75-2\right)\left(2.75-2\right)\left(2.75-1.5\right)} \\ \Rightarrow \mathrm{A}=\sqrt{2.75\times 0.75\times 0.75\times 1.25}=\sqrt{1.93359375}=1.39 {\mathrm{cm}}^2 \\ \mathrm{So} \mathrm{total} \mathrm{nuber} \mathrm{of} \mathrm{shaded} \mathrm{triangles} \mathrm{are} 4 \\ \mathrm{Hence} \mathrm{total} \mathrm{area} \mathrm{of} \mathrm{shaded} \mathrm{triangle}=4\times \mathrm{Area} \mathrm{of} \mathrm{one} \mathrm{shaded} \mathrm{triangle} \\ \Rightarrow \mathrm{Total} \mathrm{area}=4\times 1.39=5.56 {\mathrm{cm}}^2 \mathrm{Answer} \end{gathered}$$


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