suppose 10 rase to power -17J of light energy is needed by the interior of the human eye to see on object. how many photons of green light ( wavelenght = 550nm) are needed to generate this minimum amount of energy?

Dear Student,

Please find below the solution to the asked query:

Energy of a single photon: $E=\frac{hc}{\lambda }=\frac{6.626\times {10}^{-34} Js \times 3\times {10}^8 m{s}^{-1}}{550\times {10}^{-9} m}=3.61\times {10}^{-19}J$

Number of photons required = $\frac{1\times {10}^{-17}}{3.61\times {10}^{-19}}=\mathbf{28}\mathbf{ }\mathit{p}\mathit{h}\mathit{o}\mathit{t}\mathit{o}\mathit{n}\mathit{s}$


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