Suppose ABC is a triangle with 3 acute angles A, B and C. The points whose co ordinates are (cos B - sinA, sin B- cos A) can be in the :-
1) 1st and 2nd quadrant
2) 2nd and 3rd quadrant
3) 3rd and 4th quadrant
4) 2nd qudrant only
Please answer with proper explanation

Dear student
Since ABC is a acute angle Therefore,A+B>π2A>π2-BsinA-cosB>0cosB-sinA<0    ...(1)Again,B>π2-AsinB>cosAsinB-cosA>0     ...(2)From (1) and (2) x-coordinate is -ve and y-coordinate is +velie in 2nd quadrant only
Regards

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