T'AT is a tangent drawn to the circle with center O . If angle BAC = 50 degree ,find angle BAT and angle BCA .Also find angle DAB+angle DCB Share with your friends Share 16 Manbar Singh answered this We know that tangent to a circle is always ⊥ to its radius at the point of contact.Now, T'AT is a tangent to the circle at point A.So, OA⊥T'AT or ∠OAT = 90°Now, ∠OAT = 90°⇒∠CAT = 90°⇒∠CAB + ∠BAT = 90°⇒50° + ∠BAT = 90°⇒∠BAT =40°Now, ∠ABC = 90° Angle in a semicircle is a right angleIn ∆ABC,∠ABC + ∠BAC + ∠BCA = 180° Angle sum property⇒90° + 50° + ∠BCA = 180°⇒140° + ∠BCA = 180°⇒∠BCA = 40°Now, ABCD is a cyclic quadrilateral, then∠DAB + ∠DCB = 180° Opposite angles of cyclic quadrilateral are supplementary 30 View Full Answer Surendar answered this liugk -11 Bhakti answered this BAT=140 , BCA= 40, DAB= 100, DCB= 80 -6 Naman answered this Well bro this ques is of ulike...anyways this pic is its ans and remaining is below 8 Naman answered this Well bro this ques is of ulike...anyways this pic is its ans and remaining is below 5 Naman answered this As i told..remaining part... 14 Naman answered this Xxx -3