tan theta + tan 2 theta +√3 tan theta tan2theta=√3 Share with your friends Share 0 Abhishek Kr. Jha answered this Dear student, Here is the solution of your asked query: tanθ+tan2θ+3tanθ tan2θ=3⇒tanθ+tan2θ=3-3tanθ tan2θ⇒tanθ+tan2θ=31-tanθ tan2θ⇒tanθ+tan2θ1-tanθ tan2θ=3⇒tanθ+2θ = tanπ3 {since tanA+tanB1-tanA tanB=tanA+B}⇒θ+2θ=π3 ⇒3θ=π3⇒θ=π9 Regards 0 View Full Answer Krithikha B answered this Solve the equation 0 Ravi Gupta answered this Please find this answer 0