Taxi charges in a city consist of fixed charges per day the remaining depending upon the distance travelled in Kilometres.if a person travels 110Km , he pays Rs 1130 , for travelling 200Km , he pays Rs 1850. Find the fixed charges per day the rate per Km.
let the fixed price for taxi charge be = x
extra distance in in kilometer be = y
According .To .Question
- first equation as he travelled 110 km this goes as fixed charge + remaning distance charge
- x+ 110y = 1130 ----------------------------( 1 )
- second equation as he travelled 200 km this goes as fixed charge + remaning distance charge
x + 200y = 1850 --------------------------( 2 )
eliminate ( 1 ) and ( 2 )
x + 200y = 1850
x+ 110y = 1130 first step change the signs x will cancel away it will give
-90y = -720
y = 720
90
y = 720 divided by 90 y= 8
x + y ( 8 ) =1130
x +880 = 1130
x = 250
fixed charge = 250 rs
additonal charges per km =8 rs