Taxi charges in a city consist of fixed charges per day the remaining depending upon the distance travelled in Kilometres.if a person travels 110Km , he pays Rs 1130 , for travelling 200Km , he pays Rs 1850. Find the fixed charges per day the rate per Km.

let the fixed price for taxi charge be = x

extra distance in in kilometer be = y

According .To .Question

  1. first equation as he travelled 110 km this goes as fixed charge + remaning distance charge
  2. x+ 110y = 1130 ----------------------------( 1 )
  3. second equation as he travelled 200 km this goes as fixed charge + remaning distance charge

x + 200y = 1850 --------------------------( 2 )

eliminate ( 1 ) and ( 2 )

x + 200y = 1850

x+ 110y = 1130 first step change the signs x will cancel away it will give

-90y = -720

y = 720

90

y = 720 divided by 90 y= 8

x + y ( 8 ) =1130

x +880 = 1130

x = 250

fixed charge = 250 rs

additonal charges per km =8 rs

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