# Tell the correct option of the below question

Dear Student,

The answer is the first one.

Molar mass of O = 16 gram and Molar mass of N = 14 gram

Molar mass of O_{2} = 32 gram (16*2), Molar mass of O_{3} = 48 grams (16*3)

Molar mass of N_{2} = 28 grams (14*2)

Now, 1 mole of a compound has 6.022*10^{23} molecules

32 gram O_{2} has 6.022*10^{23} molecules of O_{2} or 12.044*10^{23 }atoms of O (since 1 mole of O_{2} contains 2 atoms of O)

Hence, 1 gram O_{2} has (12.044*10^{23 })/ 32 atoms of O = 6.022*10^{23 }/ 16 atoms of O

Similarly, 1 gram O_{3} has (18.066*10^{23} )/ 48 atoms of O = = 6.022*10^{23 }/ 16 atoms of O

Now similarly For N, 1 gram N_{2} has (12.044*10^{23 })/ 28 atoms of N = 6.022*10^{23 }/ 14 atoms of N

2 gram N has = 2* 6.022*10^{23 }/ 14 atoms of N = 6.022*10^{23 }/ 7 atoms of N

Here, 1 gram N_{2} is not equal to 2 grams N.

Hence, the correct option is the first one, 1 gm O_{2}= 1gm O_{3}

Regards

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