Tell the correct option of the below question

Dear Student,

The answer is the first one.

Molar mass of O = 16 gram and Molar mass of N = 14 gram
Molar mass of O2 = 32 gram (16*2), Molar mass of O3 = 48 grams (16*3)
Molar mass of N2 = 28 grams (14*2)

Now, 1 mole of a compound has 6.022*1023 molecules
32 gram O2 has 6.022*1023 molecules of O2 or 12.044*1023 atoms of O (since 1 mole of O2 contains 2 atoms of O)
Hence, 1 gram O2 has (12.044*1023 )/ 32 atoms of O = 6.022*1023 / 16 atoms of O
Similarly, 1 gram O3 has (18.066*1023 )/ 48 atoms of O = = 6.022*1023 / 16 atoms of O

Now similarly For N, 1 gram N2 has  (12.044*1023 )/ 28 atoms of N = 6.022*1023 / 14 atoms of N
2 gram N has =  2* 6.022*1023 / 14 atoms of N = 6.022*1023 / 7 atoms of N
Here, 1 gram N2 is not equal to 2 grams N.

Hence, the correct option is the first one, 1 gm O2= 1gm O3
 

Regards

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