Ten years ago a father was six times as old as his daughter after 10years he will be twice as old as his daughter determine their present ages Share with your friends Share 0 Varun Rawat answered this Dear Student,Let the age of daughter 10 years ago = x yrsThen the age of father 10 years ago = 6x yrsPresent age of daughter = x+10 yrsPresent age of father = 6x + 10 yrsAge of daughter after 10 yrs = x+20 yrsAge of father after 10 yrs = 6x + 20 yrsNow, according to question :6x + 20 = 2x + 20⇒6x + 20 = 2x + 40⇒6x - 2x = 40 - 20⇒4x = 20⇒x = 204 = 5So, present age of daughter =x+10 yrs = 5 + 10 = 15 yrsPresent age of father = 6x+10 yrs = 6 × 5 + 10 = 30 + 10 = 40 yrsRegards -1 View Full Answer