Ten years ago a father was six times as old as his daughter after 10years he will be twice as old as his daughter determine their present ages

Dear Student,Let the age of daughter 10 years ago = x yrsThen the age of father 10 years ago = 6x yrsPresent age of daughter = x+10 yrsPresent age of father = 6x + 10 yrsAge of daughter after 10 yrs = x+20 yrsAge of father after 10 yrs = 6x + 20 yrsNow, according to question :6x + 20 = 2x + 206x + 20 = 2x + 406x - 2x = 40 - 204x = 20x = 204 = 5So, present age of daughter =x+10 yrs =  5 + 10 = 15 yrsPresent age of father = 6x+10 yrs = 6 × 5 + 10 = 30 + 10 = 40 yrsRegards

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