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Q. If y₁ = 5 (mm) sin $\mathrm{\pi }$t is equation of oscillation of source S₁ and y₂ = 5 (mm) sin ($\mathrm{\pi }$ t + $\mathrm{\pi }$/6) be that of S₂ and it takes 1 sec and 1/2 sec for the transverse waves to reach point A from sources S₁ and S₂ respectively then the resulting amplitude at point A, is :-
         
                  
   $\left(1\right) \sqrt{2 +\sqrt{3}} \mathrm{mm}$                                  (2) $5\sqrt{3} /2$mm

   (3) 5 mm                                                  (4) $5\sqrt{2}$mm