The 20th o e
Dear student,
For B1 and B4 the contribution due to the different sections add up. For B2 and B3, the contribution due to the outer sections oppose the contribution due to the inner sections. Thus B1 and B4 are greater than B2 and B3. For B4, there is section with radius < b and hence, it contributes more than the semicircular section of radius b for B1. Thus, B4 > B1 For B3 there is a section with radius > b and hence it contrubutes less than the semicircular section of radius b for B2. Thus B3 < B2 Hence B4 > B1 > B2 > B3.
Option c is correct.
Regards
For B1 and B4 the contribution due to the different sections add up. For B2 and B3, the contribution due to the outer sections oppose the contribution due to the inner sections. Thus B1 and B4 are greater than B2 and B3. For B4, there is section with radius < b and hence, it contributes more than the semicircular section of radius b for B1. Thus, B4 > B1 For B3 there is a section with radius > b and hence it contrubutes less than the semicircular section of radius b for B2. Thus B3 < B2 Hence B4 > B1 > B2 > B3.
Option c is correct.
Regards