The 3mole of an H2gas are compressed isothermally and reversibilly from 60lto 20l and 8.59KJ of work is done on it,assume in ideal behaviour .calculate the temperature of gas.

As we know,
work done by the gas= -(work done on the gas) =2.303 x nRT log  (v/v0) 
8590 = 2.303 x 3x8.31 x  T log(20/60)
-149.615 =​ T log(20/60)
-149.615 = T (-0.4771)
T= 313.59K= 40.590C
HOpe this helps!

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