The acceleration-time graph for a particle moving along x-axis is shown in figure. If the initial velocity of particle is –5 m/s, the velocity at t = 8 s is


 (1) +15 m/s                 (2) +20 m/s               (3) – 15 m/s               (4) –20 m/s

Dear student,v=u+at from first equation of motionv=-5+(0)8v=-5m/s at t=6secondfor next 2secu=-5m/st=2sa=-10m/s2v=-5+(10)×2v=15m/shence velocity after t=8sec will be 15m/sRegards

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