The activation energy of a first order reaction is 30 kJ/mol at 298K. The activation energy for

the same reaction in the presence of a catalyst is 24 kJ/mol at 298K. How many times the
reaction rate has changed in the presence of a catalyst?

K = A e-Ea/RT

First reaction

K1 = A e-30000/RT

 

Second Reaction

K2 = A e-24000/RT

 

take ratio of these two equations

K1/ K2 = e-30000/RT / e-24000/RT

Take Ln both side

Using R = 8.314 and T = 298K

 

Ln(K1/K2) = -2.42

K1/K2 = 0.09

K2 = 11.24 times faster than first reaction.

 

Thanks.

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