The activation energy of a first order reaction is 30 kJ/mol at 298K. The activation energy for
the same reaction in the presence of a catalyst is 24 kJ/mol at 298K. How many times the
reaction rate has changed in the presence of a catalyst?
K = A e-Ea/RT
First reaction
K1 = A e-30000/RT
Second Reaction
K2 = A e-24000/RT
take ratio of these two equations
K1/ K2 = e-30000/RT / e-24000/RT
Take Ln both side
Using R = 8.314 and T = 298K
Ln(K1/K2) = -2.42
K1/K2 = 0.09
K2 = 11.24 times faster than first reaction.
Thanks.