The altitude of a right triangle is 7cm less than its base. If the hypotenuse is 13cm,find the other two sides

5cm and 12 cm

Can you give solution

If u need steps then ask

Hope u understood.

let altitude be x then base =x+7
13^2=x^2+(x+7)^2
169=x^2 + x^2 +49+14x
0=2x^2+14x-120
0=x^2+7x-60
0=x^2+12x-5x-60
0=x(x+12)-5(x+12)
0=(x-5)(x+12)
x=5,-12(notpossible)
hence altitude =5cm and base=5+7=12cm

Now r u clear