the amplitude of a shm reduces to 1/3 in first 20 second then in first 40 seconds its amplitude becomes _ ???

Dear student
Amplitude in case of damped simple harmonic motion isA(t)=A0e-bt2m....1Amplitude reduces to A03 in time t=20 sec.Putting in eqn 1A03=A0e-b×202m...213=e-b×202mLet amplitude become A1 after a time 40secA1=A0e-b×402m....3Squaring equation ...2 on both sides19=e-b×402m Putting the value of e-b×402m in eqn ...3A1=A0e-b×402m.A1=A0×19So amplitude reduces to 19 in the first 40 secondsRegards

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