the Angeles of quadilatral (x+18), (2x -14), (2x ), (x+20).find the value of x find the largest angle

sum of all angles of quadrilateral=360
x+18+2x- 14+2x+x+20 = 360
2(2x) + 2x + 38 - 14 =360
4x + 2x + 24 =360
6x = 360-24
x = 336/6=56

angle 1 = x+18 = 56+18 =74
2 = 2(56) - 14 =112-14 =98
3 = 2(56) = 112
4 = 56+20 = 76
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x+18+2x-14+2x+x+20=360
x+2x+x+2x=360-18+14-20
6x =336
x =336/6
=56
so x=56
The largest angle is 112
  • 1
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