the Angeles of quadilatral (x+18), (2x -14), (2x ), (x+20).find the value of x find the largest angle
sum of all angles of quadrilateral=360
x+18+2x- 14+2x+x+20 = 360
2(2x) + 2x + 38 - 14 =360
4x + 2x + 24 =360
6x = 360-24
x = 336/6=56
angle 1 = x+18 = 56+18 =74
2 = 2(56) - 14 =112-14 =98
3 = 2(56) = 112
4 = 56+20 = 76
x+18+2x- 14+2x+x+20 = 360
2(2x) + 2x + 38 - 14 =360
4x + 2x + 24 =360
6x = 360-24
x = 336/6=56
angle 1 = x+18 = 56+18 =74
2 = 2(56) - 14 =112-14 =98
3 = 2(56) = 112
4 = 56+20 = 76