• The angle between the tangents to the parabola y2=4axat the points where it intersects with the line x-y-a=0 is a]3.14/3
b]3.14/4
c]3.14/6
d]3.14/2
  • ​The area of the triangle formed by the tangent and the normal to the parabola y2=4ax,both drawn at the same end of the latusrectum, and the axis of the parabola is
a]2.82a2
b]2a2
c]4a2
d]none of these
  • ​y=x+2 is any tangent to the parabola y2=8x. The point P on this tangent is such that the other tangent from it which is perpendicular it is
a](2,4)
b](-2,0)
c](-1,1)
d](2,0)
  • Angle between the tangents to the curve y=x2-5x+6 at the points (2,0) and (3,0) is
a]3.14/2
b]3.14/3
c]3.14/6
d]3.14/4
  • Radius of the circle that passes through origin and touches the parabola y2=4ax at the point (a,2a) is
a]3.546a
b]2.82a
c]1.58a
d]2.12a
  • The mirror image of the parabola y2=4x in the tangent to the parabola at the point (1,2) is
a](x-1)2=4(y+1)
b](x+1)2=4(y+1)
c](x+1)2=4(y-1)
d](x-1)2=4(y-1)
  • If the line x+y=1 touches the parabola y2-y+x=0, then the coordinates of the point of contract are
a](1,1)
b](0.5,0.5)
c](0,1)
d](1,0)

4) Here is the link for the answer to one of your query:
https://www.meritnation.com/ask-answer/question/prove-that-the-tangents-to-the-curve-y-x-2-5x-6-at-the-point/application-of-derivatives/8331785

We request you to post different queries in different threads.

  • 5
What are you looking for?