The angles of a quadrilateral are in a.p. whose common difference is 10degree.Find the angles.
let one of the angles be a
so other angles will be.....
a+10, a+20,a+30 (as the common difference is 10 degree)
a + (a+10) + (a+20) + (a+30) = 360 (angle sum property of a quadrilaterral)
4a + 60 = 360
4a = 300
a = 75..................a + 10 = 75 + 10= 85
similarly substitute value of a for all the 4 angles
answer will be....... 75,85,95,105 degrees