# THE ANGLES OF A TRIANGLE ARE IN A.P.THE GREATEST ANGLE IS TWICE THE LEAST.FIND ALL THE ANGLES OF THE TRIANGLE.

let the angles of the triangle which r in AP be a-d, a, a+d

by angle sum property of triangle,

a-d+a+a+d = 180

3a = 180

a = 60

by the given condition,

a+d = 2(a-d)

a+d = 2a-2d

-a = -3d

a = 3d

3d = 60

d = 20

Therefore the angles of the triangle are,

a-d = 60-20 = 40

a = 60

a+d = 60+20 = 80

the angles of the triangle are 40,60,80

hope this helps

thumbs up plzzz

• 203

let the angles be a,a+d,a+2d.

Let a+2d be the greatest.

Then, a+2d=2a

which implies, 2d=a

now, a+a+d+a+2d=180

so 3a+3d=180

so a + d = 60

2d+d=60

d=20

which implies a = 40

so the angles are 40, 60, 80.

Hope u understood.. :D

• 26

let the least angle be x

then the other angles are x+d and x+2d

where d is the common difference

x+x+d+x+2d=180o

3x+3d=180o

x+d=60

d=60-x  ---------(1)

here the largest angle is x+2d

by the data

x+2d=2x

->d=x/2 -----------(2)

(1) and (2) gives,

60-x=x/2

x=40o

d= 40/2=20

thus the angles are 40o,60o,80o

40o+60o+80o=180o

Hope it helps.

• 15

let the angles be a,a+d,a+2d.

Let a+2d be the greatest.

therefore, a+2d=2a

thus, 2d=a

, a+a+d+a+2d=180

so 3a+3d=180

a + d = 60

2d+d=60

d=20

therfore a = 40

so the angles are 40, 60, 80.

• 16

I  GOT THE  ANSWER !!!! BUT ANYWAY ,THANKS  GUYS !!!!

AND ALL THE BEST !!!!!

• -7

I WOULD GIVE YOU ALL A THUMBS UP !!!!!!

DONT WORRYYYYYYYYY !!! BE HAPPYYYYYYYYY !!!!

• -2

Thank you bharath

• -2

thanx

• -4
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