The area enclosed by the curves y =x2, y =x3, x =0 and x =p, where p is greater than - Maths - Application of Integrals

Question

The area enclosed by the curves y =x2, y
=x3, x =0 and x =p, where p is greater than 1,
is 1/6 Then p equals
a 8/3
b 4/3
c 16/3
d 2

Vipin Verma · Accepted Answer

P greater than 1 is not possible, you cam check it by own by
finding the intersection point of both curves, you will get x = 0
,1
And the area bounded between these two curve will come as 1/12
Please check your question

The area enclosed by the curves y =x2, y =x3, x =0 and x =p, where p is greater than 1, is 1/6. Then p equals a. 8/3 b. 4/3 c. 16/3 d. 2

The area enclosed by the curves y =x², y =x³, x =0 and x =p, where p is greater than 1, is 1/6. Then p equals

a. 8/3

b. 4/3

c. 16/3

d. 2