The area of a rectangle gets reduced by 9 square units, if its length is reduced by 5 units and breadth is increased by 3 units. If we increase the length by 3 units and the breadth by 2 units, the area increases by 67 square units. Find the dimensions of the rectangle.

Can you do this question by Elimination Method??

We know that the area of rectangle is of the form xy where length=x and breadth=y

Now according to QUESTION,

(x-5)(y+3)=xy-9--(i)

(x+3)(y+2)=xy+67---(ii)

On solving the 2 equations,we get

  • xy+3x-5y-15=xy-9

             -->3x-5y=6--(iii)

  • xy+2x+3y+6=xy+67

             -->2x+3y=61(iv)

              NOW BY ELIMINATION METHOD,

               6x-10y=12(v)

               6x+9y=183(vi)

               On subtracting (vi) from (v),we get

                -19y=-171

           =>   y=9

                On substituting y=9 in (vi),we get

                 6x+81=183

           => 6x=102   (6x+9y=183 where y=9 is substituted in this equation)

           So, x=17

Therefore,the dimensions of the rectangle are:

  • Length(x)=17 units
  • Breadth(y)=9  units

Hope this is clear to you and you would a good idea of how to solve this word problem.

                                   

               

  • 115

Let length and breadth of rectangle be x unit and unit respectively.

Area = xy

According to the question,

By cross-multiplication method, we obtain

Hence, the length and breadth of the rectangle are 17 units and 9 units respectively

  • 7

no i want the answer by Elimination Method!

  • -9

 Hope it helps u to get a good idea of how to solve this problem

  • 13
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