the area of a triangle,whose base and corresponding altitude are 5.2 and 7cm is equal to the area of right triangle whose one of the sides containing the right angle is 3.5cm .Find the other side of the triangle

Base of first right  = 5.2 cmheight of first right  = 7 cmArea of first right  = 12×base×height = 12×5.2×7 = 18.2 cm2Let the base of other right  = 3.5 cmLet the height of other right  = x cmNow, area of other right  =  12×base×heightArea of first right  = 12×3.5×x18.2 = 1.75xx = 18.21.75 = 10.4 cm

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