the base BC of an equilateral triangle ABC lies on y axis . the coordinates of point C are (0,-3). if the origin is the mid point of the base , find the coordinates of the points A and B.. please do not give links and give proper explanation

Dear Student,

given: ABC is an equilateral triangle . BC lies on y-axis and origin is the midpoint of BC.

let the coordinates of B are (0,y), since it lies on y-axis

therefore the coordinates of B are y-3/2=0 i.e. y=3 coordinates are (0,3)

therefore BC = 3-(-3)=3+3=6 units

OA is the perpendicular bisector of BC therefore the vertex A will lie on OA i.e. x-axis

let the coordinates of A are (x,0). since ABC is an equilateral triangle

AB = BC

thus the coordinates of A are

Regards.

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