THE BASE BC OF TRIANGLE ABC IS DIVIDED AT D SO THAT BD=1/3 BC. PROVE THAT ar (triangleABD) =1/2 ar (triangle ADC). Share with your friends Share 1 Varun.Rawat answered this Refer the following link :https://www.meritnation.com/ask-answer/question/bc-of-the-triangle-abc-is-divided-at-bd-so-that-3bd-bc/areas-of-parallelograms-and-triangles/3928161 3 View Full Answer