1. The base of an equilateral triangle lies along the line 9x+4oy-50=0 and its vertex lies on the line 9x+40y+32=0.Find the length of each side of the triangle and also find its area?
2. A traingle is formed by the the lines 3x+4y-60=0, 12x+5y-3=0 and 4x-3y+12=0.Find the internal bisector of the angle opposite to the sides 3x+4y-6=0?
3. The two sides of a square lie on the lines 5x-12y+26=0 and 5x-12y-65=0.Find its area?

1)
The base of the equilateral triangle lies on the line = 9x+40y-50=0
and it's vertex lies on the line, 9x+40y+32=0
As we can see that slop of first line = slop of second line = $\frac{-9}{40}$
So these two lines are parallel and hence there is no fix distance between these two lines and hence making an unique equilateral triangle is not possible as distance can be varied and hence the side will be varied according to the distance between these two parallel lines . So length cannot be uniquely determined and neither the area.

3)
The two sides of the square lies on the line 5x-12y+26=0 and 5x-12y-65=0
and we can again see that both these lines are parallel .
So these two lines are parallel and hence there is no fix distance between these two lines and hence making an unique square is not possible as distance can be varied and hence the side will be varied according to the distance between these two parallel lines . So length cannot be uniquely determined and neither the area.