the ceiling of a long hall is 25 m high . what is the maximum horizontal distance that a ball thrown with a speed of 40 m/s can go without hitting the ceiling of the hall ?
the maximum possible height a projectile attains is given as
H = u2sin2θ / g
or the angle of projection will be given as
sinθ = [Hg / u2]1/2
here,
H = 25m
u = 40 m/s
g = 10 m/s2
so,
sinθ = [(25x10) / 402]1/2
or
sinθ = 0.559
thus,
θ = 34 degree
now,
the maximum horizontal range will be
R = u2sin2θ / g
= 402sin(2x34) / 10
thus, we get
R = 148.3 m